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Post by Felix on Sept 25, 2016 9:02:54 GMT -5
Oh no. Now that is hard to explain. My friend, who is not bad at maths by any means, cannot do those.
Anyway, how I do it. I'm going to use yours as an example. Firstly I look at the 7z². There is only 1 nice pair to make 7, 1 and 7. So put those brackets down - (7z )(z ) Next is looking at the -2. Two numbers that multiply to make that. There are 2 pairs: -2 and 1; 2 and -1. So then you just have to look at it with logic. This can take a lot of practice.
You have to make -5 by adding result of multiplying the two inside numbers and the two outside numbers. ( X)(X ) + (Y )( Y) That might take a lot of looking at, but try to keep numbers small.
Now, I don't think that's too good of an explanation, so... Yeah...
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Post by Deleted on Sept 25, 2016 9:04:58 GMT -5
i don't think you can do that one? like that specific problem. do you have any specific problems?
edit;; o no i messed up ): this is why u write down your process kiddos
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Post by Felix on Sept 25, 2016 9:07:11 GMT -5
For reference, I got (7z + 2)(z - 1)
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:10:04 GMT -5
i don't think you can do that one? like that specific problem. do you have any specific problems? I only get one at a time as it's a computer program. Here's another example: 5z 2 +27z+10 I know that I need to factor 5z 2 and 10 together and then factor out the answer like so: 5z 2 +25z+2z+10. Now I get stuck here
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Post by Deleted on Sept 25, 2016 9:13:41 GMT -5
i don't think you can do that one? like that specific problem. do you have any specific problems? I only get one at a time as it's a computer program. Here's another example: 5z 2 +27z+10 I know that I need to factor 5z 2 and 10 together and then factor out the answer like so: 5z 2 +25z+2z+10. Now I get stuck here i messed up in the first problem rip anyway what you do there isn't really 5z^2 + 10 it's more 5z^2 + 25z , and 2z + 10. i think ??? so like 5z^2 + 25z have a greatest common factor of 5 so you would yknow 5z(z + 5) and 2z + 10 share a GCF of 2 so 2(z + 5) and z + 5 is the same in both so you can factor that and etc yes? 5z(z+5)+2(z+5) (z+5)(5z+2) i think?
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Post by Deleted on Sept 25, 2016 9:19:03 GMT -5
As far as I understand, it go something like this: 5z 2 +27z+10 5z 2+25z+2z+10 5z(z+5)+2(z+5) Answer: (z+5) (5z+2) yeah
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:19:08 GMT -5
I only get one at a time as it's a computer program. Here's another example: 5z 2 +27z+10 I know that I need to factor 5z 2 and 10 together and then factor out the answer like so: 5z 2 +25z+2z+10. Now I get stuck here i messed up in the first problem rip anyway what you do there isn't really 5z^2 + 10 it's more 5z^2 + 25z , and 2z + 10. i think ??? so like 5z^2 + 25z have a greatest common factor of 5 so you would yknow 5z(z + 5) and 2z + 10 share a GCF of 2 so 2(z + 5) and z + 5 is the same in both so you can factor that and etc yes? I think that's what I got. I get confused when there are two different signs because you want two to match perfectly, right?
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Post by Deleted on Sept 25, 2016 9:23:22 GMT -5
Why are you asking for math help on a cat forum, Bleaky?
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Post by Felix on Sept 25, 2016 9:24:17 GMT -5
I don't actually do it the way you're all describing. I just look at the numbers and I can usually just write it down... I don't want to confuse anyone, so I'm not going to say anything more.
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:24:49 GMT -5
Why are you asking for math help on a cat forum, Bleaky? Because my desperation has driven me mad
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Post by Deleted on Sept 25, 2016 9:25:28 GMT -5
Alright, here's where I get confused: 3x 2+11z-14 -42 11 the numbers would be -14 and 3 ? so like 3x^2 -14x + 3x - 14 x(3x - 14) + 1(3x-14) (3x-14)(x+1) yeah?
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Post by Deleted on Sept 25, 2016 9:25:30 GMT -5
Why are you asking for math help on a cat forum, Bleaky? Because my desperation has driven me mad Okay...
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:25:50 GMT -5
I don't actually do it the way you're all describing. I just look at the numbers and I can usually just write it down... I don't want to confuse anyone, so I'm not going to say anything more. If it helps any, I'm doing the AC method. It is the least confusing method for me
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:27:13 GMT -5
Alright, here's where I get confused: 3x 2+11z-14 -42 11 the numbers would be -14 and 3 ? so like 3x^2 -14x + 3x - 14 x(3x - 14) + 1(3x-14) (3x-14)(x+1) yeah? My question is how to make the parenthesis match? Wait, I think I might understand...though I'm not sure yet
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Post by Deleted on Sept 25, 2016 9:32:02 GMT -5
-42 11 the numbers would be -14 and 3 ? so like 3x^2 -14x + 3x - 14 x(3x - 14) + 1(3x-14) (3x-14)(x+1) yeah? My question is how to make the parenthesis match? Wait, I think I might understand...though I'm not sure yet oh okay you have to find the greatest common factor. aka the largest number that goes into both other numbers. so if you had like 8 and 24, the GCF {greatest common factor} would be 8. so you'd divide both by eight. so if it was like 8x-24 you'd make it into 8(x-3) the way to get the parenthesis to match is yknow having a GCF that would make them match. lol. like since 1 was the GCF of the last problem, the ONLY way to get the parenthesis to match was having 3 and 14 be the numbers you use on both sides. i'm not sure if i'm explaining well or making it complicated or etc so i'll stop now oops
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:34:07 GMT -5
My question is how to make the parenthesis match? Wait, I think I might understand...though I'm not sure yet oh okay you have to find the greatest common factor. aka the largest number that goes into both other numbers. so if you had like 8 and 24, the GCF {greatest common factor} would be 8. so you'd divide both by eight. so if it was like 8x-24 you'd make it into 8(x-3) the way to get the parenthesis to match is yknow having a GCF that would make them match. lol. like since 1 was the GCF of the last problem, the ONLY way to get the parenthesis to match was having 3 and 14 be the numbers you use on both sides. i'm not sure if i'm explaining well or making it complicated or etc so i'll stop now oops the answer you gave was wrong, and I'm trying to figure out why. You did the same as me and had a wrong sign
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Post by Felix on Sept 25, 2016 9:34:37 GMT -5
What problem are you currently working on?
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:36:54 GMT -5
What problem are you currently working on? 2z 2 -9z+7
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Post by Felix on Sept 25, 2016 9:38:18 GMT -5
What problem are you currently working on? 2z 2 -9z+7 How far have you gotten with that question?
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Bleak
RN does not stand for Refreshments and Narcotics
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Post by Bleak on Sept 25, 2016 9:46:38 GMT -5
How far have you gotten with that question? I multiply A (2z 20 and C (7) together and get 14. I factor ou 14 to replace the 9z with two numbers of 14. 2z 2 -7z -2z +7 Now I get stuck because of the +7, I think
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Post by Deleted on Sept 25, 2016 9:52:07 GMT -5
oh okay you have to find the greatest common factor. aka the largest number that goes into both other numbers. so if you had like 8 and 24, the GCF {greatest common factor} would be 8. so you'd divide both by eight. so if it was like 8x-24 you'd make it into 8(x-3) the way to get the parenthesis to match is yknow having a GCF that would make them match. lol. like since 1 was the GCF of the last problem, the ONLY way to get the parenthesis to match was having 3 and 14 be the numbers you use on both sides. i'm not sure if i'm explaining well or making it complicated or etc so i'll stop now oops the answer you gave was wrong, and I'm trying to figure out why. You did the same as me and had a wrong sign are you sure? building it back up you get 3x^2 + 3x - 14x - 14. which is right. ? or am i doing something wrong ):
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Post by Felix on Sept 25, 2016 9:52:44 GMT -5
I've looked at the AC method. Don't you have to put the smaller number on the left?
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